Question
$3-6$ Set up an integral that represents the length of the curve. Then use your calculator to find the length correct to four decimal places.$$x=y^{2}-2 y, \quad 0 \leqslant y \leqslant 2$$
Step 1
We differentiate with respect to $y$ to get $\frac{dx}{dy} = 2y - 2$. Show more…
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$3-6$ Set up an integral that represents the length of the curve. Then use your calculator to find the length correct to four decimal places. $$y=x e^{-x}, 0 \leqslant x \leqslant 2$$
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