00:01
So in this question, we're given that an oscillator consisting of a block spring system with a mass of 0 .5 kilograms is set into oscillations with amplitude of 3 .5 centimeters, which is equal to 0 .35 meters, and repeats this motion every 0 .5 seconds.
00:21
Then we're asked to find the period, the frequency, the angular frequency, the spring constant, the maximum speed, and the magnitude of the maximum force on the.
00:30
Block due to the spring of given these initial conditions so for a for the period for the period what so some background so like the bit of background that we need for this question so since we're gonna assume simple harmonic motion so then we can assume that it oscillates it the displacement that is oscillates where the distance that oscillates by is given by x or the distance that oscillates by is given by x equal the a which is amplitude times cost of omega, the angular frequency by t at the time.
01:05
And then the velocity is given by, of course, then the derivative of x, which is the minus omega a sign of omega t.
01:17
Then for part eight, so we know that, so priority we're asked for the period.
01:24
So the period by definition is the time for repetition.
01:26
So that means that the period is just equals of what we're given.
01:30
So that's equal to 0 .5 seconds.
01:34
Then for part b, we're asked what the frequency is, so we know that the frequency is equal to 1 over the period, which is equal to 1 over 0 .5 seconds, which is equal to which is equal to 2 hertz, if we work this out, since the unit of inverse seconds is hertz.
01:59
Then for part c, we're asked what the angular frequency is, so angular frequency, omega is equal to 2.
02:06
2 pi times the frequency f.
02:10
So this is equal to if we work it out 2 pi times 2 hertz, which is equal to 4 pi, and this is in units of rads per second, which is approximately equal to 12 .57 rads per second.
02:32
Then for part d, we're asked, what is the spring constant? so we know what the relationship between angular frequency and the spring constant is.
02:40
So omega is equal to the square root of the spring constant k over the mass of the particle.
02:46
And this is true for a spring mass system.
02:50
So then rearranging this, we get that k is equal to omega squared times the mass.
03:02
And if we work this out, then this is equal to, so if we square it, so this is equal to 12 .9, 12 .57.
03:14
Squared, 12 .57 squared multiplied by mass, which is 0 .5, which is equal to 0 .5 kilogram, so 0 .5.
03:25
And if we work this out, this is equal to, so this is equal to 7 .81, and the units are newtons per meter.
03:43
Sorry, there's a mistake here.
03:45
So this, i missed a decimal place, so this is actually equal to 79 newtons per meter...