Enroll in one of our FREE online STEM summer camps. Space is limited so join now!View Summer Courses

University of Maine

Problem 1
Problem 2
Problem 3
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
Problem 72
Problem 73
Problem 74
Problem 75
Problem 76
Problem 77
Problem 78
Problem 79
Problem 80
Problem 81
Problem 82
Problem 83
Problem 84
Problem 85
Problem 86
Problem 87
Problem 88
Problem 89
Problem 90
Problem 91
Problem 92
Problem 93
Problem 94
Problem 95
Problem 96
Problem 97
Problem 98
Problem 99
Problem 100
Problem 101
Problem 102
Problem 103
Problem 104
Problem 105
Problem 106
Problem 107
Problem 108
Problem 109
Problem 110
Problem 111
Problem 113
Problem 114
Problem 115
Problem 116
Problem 117
Problem 118
Problem 119
Problem 120
Problem 121
Problem 122
Problem 123
Problem 124
Problem 125
Problem 126
Problem 127
Problem 128
Problem 129
Problem 130
Problem 131
Problem 132
Problem 133
Problem 134
Problem 135
Problem 136
Problem 138
Problem 139
Problem 140
Problem 212

Need more help? Fill out this quick form to get professional live tutoring.

Get live tutoring
Problem 116

3.116 For the reaction between solid tetraphosphorus trisulfide and oxygen gas to form solid tetraphosphorus decoxide and sulfur dioxide gas, write a balanced equation. Show the equation (see

Table 3.4 ) in terms of (a) molecules, (b) moles, and (c) grams.

Answer

P4S3(s) +8O2(g) --> P4O10(s) + 3SO2(g)

a. 1 molecule of P4S3 reacts with 8 molecules of O2 to form 1 molecule of P4O10 and 3 molecules of SO2

1 mole of P4S3 reacts with 8 moles of O2 to form 1 mole of P4O10 and 3 moles of SO2

c. 220.093g of P4S3 reacts with 255.984g of O2 to form 288.886g of P4O10 and 192.174g of SO2

You must be logged in to like a video.

You must be logged in to bookmark a video.

## Discussion

## Video Transcript

give it a description of a chemical reaction. This could be written as a balanced chemical equation, which can then be interpreted in several different ways. So if, for example, we have solid tetro, phosphorus try sulfide reacts with oxygen gas to form solid tetra phosphorus dick oxide and sulphur dioxide gas. Our first step is to write the chemical formulas for each of these substances. Tetra phosphorus try sulfide contains phosphorus and tetra means four, and sulfide is so for, and there are three because of the try two solid plus oxygen gas in the chemical reaction. Oxygen gas is always +02 and it forms solid tetra phosphorus. So again, P four Decca oxide deca is the prefix for 10 plus sulphur dioxide, which is one sulfur and to Oxygen's. This is a gas, and this is a solid. Once we've written our skeletal equation, we can balance the equation by changing the coefficients we see on this side. Therefore, phosphorus is on this side. There for phosphorus is here. There are three suffers, and here there's only one, so we multiply by three. This gives us 10 oxygen's plus three more here for a total of 16 So that means the coefficient here has to be eight. So now we have a balanced equation, and we can interpret this in several different ways. If we think of it. In terms of molecules, this equation tells us the ratio of molecules that will form. So, for example, if we have one molecule of P for s three, it will react with eight molecules of oxygen to form one molecule of P for 0 10 and three molecules of sulfur dioxide. So the coefficients from the balanced equation can tell us how many molecules react with each typically because we don't do reactions and molecules, they're too small to measure out. We use moles instead. On this equation can also describe the number of moles required. So, for example, the coefficients tell us that one mole of P for S three we'll react with eight moules of 02 to form one more p for 0 10 and one mole of sulfur dioxide so it can be interpreted in terms of other molecules or moles. The third way that we can consider it is to look at it in terms of mass in the law of conservation of mass as well as the relationship between mass and moles. In order to do this, we need to know the molar mass of each substance. And so we find that by using the periodic table So one more of P four s three has the molar mass before times the molar mass of phosphorus, plus three times the molar mass of sulfur, or 200 and 20 point 093 grams. Similarly, we confined the molar mass of oxygen to be 31 0.998 grams by adding two times 15 and the molar mass of P for 0 10 is equal to 200 and 83 0.886 grams. And finally, the molar mass of sulfur dioxide is equal to 64 0.58 grams. And so we can interpret this equation in terms of grams by multiplying the molar mass by the coefficient in front of the equation. So we multiply this number by eight in this number by three, and these still are multiplied by one. So for the reaction, I need to have this many grams of each substance, and I could describe the reaction in terms of grams so it would be 220 grams of p for S three reacts with 255 went 984 grams of oxygen to form 283 grams of P for 0 10 and 192 0.174 grams of sulfur dioxide.

## Recommended Questions