3.6 gram of oxygen is adsorbed on 1.2 g of metal powder. What volume of oxygen adsorbed per gra

step 1 So mass of oxygen is 3 .6 gram and mass of metal is 1 .2 gram. So the mass absorbed mass of oxyg

3.6 gram of oxygen is adsorbed on 1.2 g of metal powder....

$3.6$ gram of oxygen is adsorbed on $1.2 \mathrm{~g}$ of metal powder. What volume of oxygen adsorbed per gram of the adsorbent at 1 atm and $273 \mathrm{~K}$ ?
(A) $0.19 \mathrm{Lg}^{-1}$
(b) $1 \mathrm{Lg}^{-1}$
(C) $2.1 \mathrm{Lg}^{-1}$
(d) None of these

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Key Concepts

Ideal Gas Law

This is a fundamental principle in physical chemistry that relates the pressure, volume, temperature, and number of moles of a gas using the equation PV=nRT. It allows us to predict the behavior of a gas under different conditions and is key to calculating quantities such as the volume occupied by a given number of moles, especially under standard conditions.

Molar Volume at STP

At standard temperature and pressure (STP), one mole of an ideal gas occupies approximately 22.4 liters. This concept is essential when converting between the amount of gas in moles and its volume, a common calculation in problems involving gas phase reactions and processes.

Adsorption

Adsorption refers to the process in which atoms, ions, or molecules adhere to a surface, forming a thin film. In the context of this problem, adsorption is used to quantify how much gas (oxygen) is taken up per unit mass of a solid adsorbent, which is an important parameter in surface science and catalysis.

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