36 ml of pure water takes 100 sec to evaporate from a vessel and heater connected to an electric

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36 ml of pure water takes 100 sec to evaporate from a vessel...

$36 \mathrm{ml}$ of pure water takes $100 \mathrm{sec}$ to evaporate from a vessel and heater connected to an electric source which delivers 806 watt. The $\Delta \mathrm{H}_{\mathrm{Vap}}$. of water is: (a) $40.3 \mathrm{KJ} / \mathrm{mole}$ (b) $406 \mathrm{KJ} / \mathrm{mole}$ (c) $80.6 \mathrm{KJ} / \mathrm{mole}$ (d) $20.15 \mathrm{KJ} / \mathrm{mole}$

$36 \mathrm{ml}$ of pure water takes $100 \mathrm{sec}$ to evaporate from a vessel and heater connected to an electric source which delivers 806 watt. The $\Delta \mathrm{H}_{\mathrm{Vap}}$. of water is:
(a) $40.3 \mathrm{KJ} / \mathrm{mole}$
(b) $406 \mathrm{KJ} / \mathrm{mole}$
(c) $80.6 \mathrm{KJ} / \mathrm{mole}$
(d) $20.15 \mathrm{KJ} / \mathrm{mole}$

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Key Concepts

Latent Heat of Vaporization

This is the amount of energy needed to transform a unit amount (typically one mole or one kilogram) of a liquid into vapor at its boiling point without a change in temperature. It reflects the strength of intermolecular bonds that must be overcome during the phase transition from liquid to gas.

Power and Energy Relationship

The relationship between power and energy is fundamental in thermodynamics: power is the rate at which energy is transferred or converted, meaning that multiplying power (in watts) by time (in seconds) gives the total energy (in joules) delivered during a process.

Mole Concept and Mass Conversion

Converting a given mass or volume of a substance to moles is crucial when dealing with molar thermodynamic properties. This involves using the substance’s density and molar mass to determine the number of moles, which then allows for the calculation of quantities like the molar latent heat of vaporization.

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