00:01
In this question we're asked to determine the period of oscillation of a performer on a trapeze, swinging from back and forth.
00:10
So we're given the period at a specific length, and then we're asked to find the new period if the center of the mass of the trapeze performer system is raised by 35 centimeters along the trapeze.
00:25
And yes, this is what we have to find them.
00:27
So we're asked to find a new period.
00:32
So t is equal question mark.
00:35
And we're given that the old period, t0, is equal to, so it's equal to 8 .8 .85 seconds.
00:52
And then we're also told that we can treat the system as a simple pendulum.
00:55
So when we think of simple pendulum and period, we always think of this formula.
01:00
So t is equal to 2 pi of the scale.
01:03
Square root of the length of the pendulum l over gravity, acceleration due to gravity.
01:10
Of course, we know that acceleration due to gravity, g is equal to, we're going to take it equal to 9 .81 meters per second squared.
01:21
So if we substitute the same, we have 2 pi square root of l, which is equal to, in this case, we're trying to find out, and we have t0, so it's up in t0...