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Problem 63

What does the term stoichiometrically equivalent …

University of Maine

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Problem 62

a. Cl + O3--> ClO + O2; 2ClO --> ClOOCl; ClOOCl --> 2Cl + O2

b. O3 + ClO --> 2O2 + Cl



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Video Transcript

given the following description of steps of an overall reaction, we can write equations for each process, as well as the overall reaction when we talk about a chlorine atom while typically and reactions were using a die atomic molecule, the chlorine atom is just CEO reacts with ozone, which is 03 to form chlorine monoxide. Chlorine monoxide is a compound that has chlorine and monoxide means one oxygen plus molecular oxygen. Molecular oxygen is 02 So our first step is written like this. We can see that it's balanced the way it's written. One chlorine on both sides. Three. Oxygen's on both sides. Our second step takes the chlorine monoxide that we formed in the first step and reacts to form this intermediates compound. Cielo Oh CEO. As it's written, there's one Korean on this side, but two Koreans on this side and one oxygen, but to so to balance it, we need to put it to here, giving us to chlorine and to oxygen's on both sides. Finally, in the third step of this process, take the intermediate that we made in Step two, and it breaks apart to make chlorine atoms which again or seal plus molecular oxygen, which is +02 again. This needs to be balanced because while there are two oxygen's on both sides, there are two Koreans on this side and only one on this side. So the equation for each step is written as follows. We can look at the overall equation by adding up. All the steps have been canceling out anything that appears on both sides. So we take all of our reactant and all of our products. Since this appears on both sides, we can cross it out and simplify, and I'm gonna combine my leg terms. So there are two oxygen's and then I can reduce terms. But since there's a chlorine on this side in two Korans on the Side and this, and to hear the overall equation is written as follows

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