Question
$(4 a)^{-2}$
Step 1
So, $(4a)^{-2} = \frac{1}{(4a)^2}$. Now, we need to square $(4a)$. Recall that $(ab)^n = a^n b^n$. So, $(4a)^2 = 4^2 a^2 = 16a^2$. Show more…
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