4 cell each of emf $2 \mathrm{v}$ and internal resistance of $1 \Omega$ are connected in parallel to a load resistor of $2 \Omega$ Then the current through the load resistor is....
(A) $2 \mathrm{~A}$
(B) $1.5 \mathrm{~A}$
(C) $1 \mathrm{~A}$
(D) $0.888 \mathrm{~A}$