00:01
Okay, so we're asked to find the absolute maximum and absolute minimum of the function f of x is equal to x times e to the negative x squared divided by 8 on the interval negative 1 to 4.
00:16
Okay, so first of all, let's look for any critical numbers.
00:20
Okay, so f prime of x is equal to, we have to use the product rule.
00:27
So we take the first function times the derivative of the second, the derivative of the e to the negative x squared over 8 is e to the negative x squared over 8 times the derivative of the inside function, which is negative 1 fourth.
00:46
And then we have the derivative of the first function, which is just 1 times the second function, which is e to the negative x squared over 8.
00:58
Okay, so notice that we can go ahead and factor out e to the negative x squared over 8.
01:05
And we have, oops, no equals, parentheses, x squared, negative x squared over four plus one.
01:16
Okay, so notice that this is always non -zero.
01:20
It's defined everywhere.
01:21
So we just need to solve this one.
01:23
Negative x squared plus over four plus one is equal to zero, or x squared over four is equal to zero.
01:37
Or x squared is equal to four.
01:40
So x is equal to plus and minus two...