00:01
Hi everyone, so what we have is a long roll of manganese of width 2 meters, thickness 0 .5 centimeters, and a density of 7 ,854 kilograms per meters cube that's rolling off a mill.
00:16
And this manganese plate rolls off at a temperature of 820 degrees c and is quenched in an oil bath to 51 .1 degree c.
00:25
And this oil is at 45 degrees celsius.
00:28
What we're asked to find is the q, or basically the heat transfer that is required to keep the oil at 45 degrees celsius when we're changing the actual velocity that the steel plate is moving from velocities from 5 meters per minute to 50 meters per minute.
00:47
So what we're going to do first is go ahead and write down the properties of our steel or manganese plate.
00:53
So we know the density, we know the density is going to be equal to 7 ,854 kilograms per meter cube.
01:06
And we know the constant, this heat value, is going to be equal to 0 .4 .34 kilojoules per kilogram degree celsius.
01:17
Now what we can do first is go ahead and solve for sulfor m dot in terms of velocity.
01:22
Remember that velocity is the parameter there.
01:25
We're going to be changing to see its effect on the rate of heat transfer that results in the oil bath.
01:31
So we know that m dot is going to be equal to row v...