$500 \mathrm{~mL}$ of a hydrocarbon gas burnt in excess of oxygen, gave $2500 \mathrm{~mL}$ of $\mathrm{CO}_{7}$ and $3000 \mathrm{~mL}$ of water vapour (at constant $\mathrm{T}$ and $\mathrm{P}$ ). The formula of the hydrocarbon is
(a) $\mathrm{C}_{3} \mathrm{H}_{6}$
(b) $\mathrm{C}_{2} \mathrm{H}_{4}$
(c) $\mathrm{C}_{5}{ }^{3} \mathrm{H}_{12}^{6}$
(d) $\mathrm{CH}_{4}$