00:05
So given ln of x is equal to 3 minus 2x, we need to prove that there is a real root.
00:15
There is at least one real root and we have to find the interval.
00:23
So let's consider f of x to be ln of x plus 2x minus 3 is equal to 0.
00:30
And using graphing with conduct, the root rise between the possible routers between no neutral.
00:46
So here we are going to use the intermediate value theorem.
00:53
So where suppose f of f is continuous and close to the a comma b and nb any number between f of a and f of b and f of a, f of a, you know t equal to a thing b there exist number c in a comma b such that f of c is compared to f.
01:33
So here first we see whether f is continuous on 1 comma 2 close into it.
01:39
So here we see we substitute the values we'll see that this continuous on and the composite function of polynomial and low bit make so now to find the value of f2 we'll find f of 1.
02:23
A line of 1 is 0...