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$^{56} \mathrm{Fe}$ is among the most tightly bound of all nuclides. It is more than 90$\%$ of natural iron. Note that $^{56} \mathrm{Fe}$ has even numbers of both protons and neutrons. Calculate BE/A, the binding energy per nucleon, for $^{56} \mathrm{Fe}$ and compare it with the approximate value obtained from the graph in Figure $31.27 .$

8.790 $\mathrm{MeV}$

Physics 103

Chapter 31

Radioactivity and Nuclear Physics

Nuclear Physics

Cornell University

Simon Fraser University

University of Winnipeg

Lectures

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Hello friends In this problem, we have to calculate binding energy per nuclear on for I had it happy 56. Let's hear the solution. Binding energy is defined it atomic number in tow. Massa Proton plus mass number minus atomic number into Mars off neutrons in tow. 9 31.56 Meg election Butch So for Ireland, atomic number is 26. Massive proton is 1.0 78 to 5. Mass number off. Iran is 56. Atomic number is 26. Mass off neutron is 1.8 665 in tow. 9. 31.56 Mega electron volt. The on solving it You are getting this 4 92 point three Mega weapon board. Hence no binding energy part nuclear for 92.3 upon 56. So it is to be 8.79 Jiro Mega Electron Volt and from winding energy graph data upon a for iron 56 is given 8.8 Meg Electron Volt, which is matching bit ever calculated value. I that son, Thanks for watching it

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