60 cal heat is produced per second in a 6 Ωresistance on passing electric current through the ci

step 1 In this question we have a electric circuit in this a resistance of 2 -on connected with series

60 cal heat is produced per second in a 6 Ωresistance on...

60 cal heat is produced per second in a $6 \Omega$ resistance on passing electric current through the circuit as shown in the figure. The amount of heat produced per second through $3 \Omega$ resistance is $\ldots \ldots \ldots \ldots$ cal
(A) 30
(B) 60
(C) 100
(D) 120

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Key Concepts

Electrical Power Dissipation in Resistive Circuits

This concept focuses on calculating the rate at which electrical energy is transformed into thermal energy in resistive components. It involves using either the I²R or V²/R formulations to determine the power (or heat per unit time) dissipated in a resistor, highlighting the role of resistance in controlling energy conversion based on the circuit's configuration.

Joule’s Law (Resistive Heating)

Joule’s Law explains how electric energy is converted into heat in a resistor, where the power dissipated as heat is proportional to the square of the current and the resistance (P = I²R) or alternatively to the square of the voltage divided by the resistance (P = V²/R). It is crucial for understanding how different resistive values affect heat production under constant voltage or current conditions.

Ohm's Law

Ohm's Law establishes the fundamental relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = IR. This law is essential for analyzing how voltage is distributed across resistive components and determining the current flow when resistors are arranged in different configurations (series or parallel).

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