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66. The distance between the centers of the two oxygen atoms in an oxygen molecule is $1.21 \times 10^{-8} \mathrm{cm} .$ What is this distance in inches?
0.4763 $\mathrm{in}$
01:27
Kevin C.
00:41
Ronald P.
Chemistry 101
Chapter 1
Essential Ideas
Intro to Chemistry
University of Maryland - University College
Brown University
University of Toronto
Lectures
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Good day. The topic is about unit conversion. Not that we can convert one you need of a certain dimension to another unit of the same dimension by using some congressional chapters. For example, we can convert inch two centimeter by noting. One inch is equal to 2.54 centimetre. Now suppose we are given with the distance between two oxygen atoms in an oxygen molecule is equal to 1.21 times 10 to the negative eight centimeter. And we wish to find or to express this distance in terms of inch. So what we'll do is to use this certain conversion factor we have here. Yeah. To convert the same quantity in terms of from centimeter two inch. So what we will do is use the dimensional analysis approach. So in this case we will multiply the given, make a fraction that is expressed as the conversion factor. Which the merit is the desired quantity in the denominator is given quantity. Were they given unit? So again, one inch is equal to 2.54 centimeters. So as we can see we can cancel a centimeter here and just stick with me. I know about notifying fraction. We will simply multiply the give in, made the numerator of the brown short and divide their product by the denominator of the fraction. And of course this is now expressed in terms of inch. So we have 1.21 times 10 to the negative eight divided by 2.54. That gives us 4.76 times 10 to the negative nine inch. So hence 1.21 times 10 to the negative eight centimeter is equal to 4.76 times 10 to the negative nine inch. So I hope that helped.
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