00:01
All right, so let's first look at part a and try to describe what the transformations are here.
00:08
So the first thing we're going to do is we're going to look at that x minus 5.
00:12
So to figure out what's happening there, you might have already heard that if it's inside the parentheses, minus means to the right and plus means to the left.
00:22
But let's just make sure we understand why.
00:25
So we know that this is going to be 5, this is going to be a shift 5 units to the right.
00:31
But why is that? imagine if we plugged zero into the original function, f of zero.
00:40
And that's just going to equal some random thing, whatever.
00:44
Let's just call it a square for now.
00:45
It could be any number.
00:46
Who knows? when i plug zero into this new function, i'm going to get f of 0 minus 5, which is going to be f of negative 5.
01:06
So zero has actually been moved five spaces to the right, because before when i would plug zero in, it was just whatever this number is.
01:21
But now when i try to plug zero in, it's taken me all the way to f of negative five.
01:28
It's almost like if here's my number line, here's zero, and here's negative five.
01:34
This used to be where zero is, but now negative 5 has shifted all the way over here, and it's in the new place where 0 used to be.
01:46
So then what do you think happened to 0? it shifted, 5 spaces over as well.
01:53
So now, to get this square that i used to get by plugging 0 in, now i would have to plug 5 in to get that square...