Enroll in one of our FREE online STEM summer camps. Space is limited so join now!View Summer Courses

Johns Hopkins University

Problem 1
Problem 1
Problem 1
Problem 1
Problem 1
Problem 1
Problem 1
Problem 1
Problem 2
Problem 2
Problem 2
Problem 2
Problem 2
Problem 2
Problem 2
Problem 2
Problem 3
Problem 3
Problem 3
Problem 3
Problem 3
Problem 3
Problem 3
Problem 3
Problem 4
Problem 4
Problem 4
Problem 4
Problem 4
Problem 4
Problem 4
Problem 4
Problem 5
Problem 5
Problem 5
Problem 5
Problem 5
Problem 5
Problem 5
Problem 5
Problem 6
Problem 6
Problem 6
Problem 6
Problem 6
Problem 6
Problem 6
Problem 6
Problem 7
Problem 7
Problem 7
Problem 7
Problem 7
Problem 7
Problem 7
Problem 7
Problem 8
Problem 8
Problem 8
Problem 8
Problem 8
Problem 8
Problem 8
Problem 8
Problem 9
Problem 9
Problem 9
Problem 9
Problem 9
Problem 9
Problem 9
Problem 9
Problem 10
Problem 10
Problem 10
Problem 10
Problem 10
Problem 10
Problem 10
Problem 10
Problem 11
Problem 11
Problem 11
Problem 11
Problem 11
Problem 11
Problem 11
Problem 11
Problem 12
Problem 12
Problem 12
Problem 12
Problem 12
Problem 12
Problem 12
Problem 12
Problem 13
Problem 13
Problem 13
Problem 13
Problem 13
Problem 13
Problem 13
Problem 13
Problem 14
Problem 14
Problem 14
Problem 14
Problem 14
Problem 14
Problem 14
Problem 14
Problem 15
Problem 15
Problem 15
Problem 15
Problem 15
Problem 15
Problem 15
Problem 15
Problem 16
Problem 16
Problem 16
Problem 16
Problem 16
Problem 16
Problem 16
Problem 17
Problem 17
Problem 17
Problem 17
Problem 17
Problem 17
Problem 17
Problem 17
Problem 18
Problem 18
Problem 18
Problem 18
Problem 18
Problem 18
Problem 18
Problem 18
Problem 19
Problem 19
Problem 19
Problem 19
Problem 19
Problem 19
Problem 19
Problem 19
Problem 20
Problem 20
Problem 20
Problem 20
Problem 20
Problem 20
Problem 20
Problem 20
Problem 21
Problem 21
Problem 21
Problem 21
Problem 21
Problem 21
Problem 21
Problem 21
Problem 22
Problem 22
Problem 22
Problem 22
Problem 22
Problem 22
Problem 22
Problem 22
Problem 23
Problem 23
Problem 23
Problem 23
Problem 23
Problem 23
Problem 23
Problem 23
Problem 24
Problem 24
Problem 24
Problem 24
Problem 24
Problem 24
Problem 24
Problem 24
Problem 25
Problem 25
Problem 25
Problem 25
Problem 25
Problem 25
Problem 25
Problem 25
Problem 26
Problem 26
Problem 26
Problem 26
Problem 26
Problem 26
Problem 26
Problem 26
Problem 27
Problem 27
Problem 27
Problem 27
Problem 27
Problem 27
Problem 27
Problem 27
Problem 28
Problem 28
Problem 28
Problem 28
Problem 28
Problem 28
Problem 28
Problem 28
Problem 29
Problem 29
Problem 29
Problem 29
Problem 29
Problem 29
Problem 29
Problem 29
Problem 30
Problem 30
Problem 30
Problem 30
Problem 30
Problem 30
Problem 30
Problem 30
Problem 31
Problem 31
Problem 31
Problem 31
Problem 31
Problem 31
Problem 31
Problem 31
Problem 32
Problem 32
Problem 32
Problem 32
Problem 32
Problem 32
Problem 32
Problem 32
Problem 33
Problem 33
Problem 33
Problem 33
Problem 33
Problem 33
Problem 33
Problem 33
Problem 34
Problem 34
Problem 34
Problem 34
Problem 34
Problem 34
Problem 34
Problem 34
Problem 35
Problem 35
Problem 35
Problem 35
Problem 35
Problem 35
Problem 35
Problem 35
Problem 36
Problem 36
Problem 36
Problem 36
Problem 36
Problem 36
Problem 36
Problem 36
Problem 37
Problem 37
Problem 37
Problem 37
Problem 37
Problem 37
Problem 37
Problem 37
Problem 37
Problem 38
Problem 38
Problem 38
Problem 38
Problem 38
Problem 38
Problem 38
Problem 38
Problem 38

Need more help? Fill out this quick form to get professional live tutoring.

Get live tutoring
Problem 11

$$7 x+3 y=8$$

$$6 x-3 y=5$$

For the solution $(x, y)$ to the system of equations

above, what is the value of $x-y ?$

$$\begin{array}{l}{\text { A) }-\frac{4}{3}} \\ {\text { B) } \frac{2}{3}} \\ {\text { C) } \frac{4}{3}} \\ {\text { D) } \frac{22}{3}}\end{array}$$

Answer

Check back soon!

SAT

SAT Practice Test # 6

You must be logged in to like a video.

You must be logged in to bookmark a video.

## Discussion

## Video Transcript

contain. So for looking for the value of X minus pi, we first have to know the value of X and y. So if we look at these equations and I could notice that these are aligned and three y and night of three by would cancel out if we added these two equations. So I'm just gonna go ahead and do that if I added seven x close six x is thirty necks three wives last night of three wise and zero. So then I'm gonna leave three. Thirteen x on the left side and then eight plus five is also thirteen. So if I have thirteen axes you two thirteen and to by both sides by thirteen, clearly I got that X is equal to what? Okay, so I found that that's already. But once I know that, I just have to find my way back. So then I'LL have to do is take that one employment either one of the equations I'm going to go and choose to put put it into the first equation playing with your seven times one cause three y is equal to eight. So then I'm going to subtract seven from both sides to get three y is equal to one, and I'm going to divide those heads by three. Giving me that Y is equal to one third. So then, if I upload that one third right back into there, I get that one. Minus one third is the value that we're looking for, which was just two thirds B.

## Recommended Questions