Question
70 calorie of heat are required to raise the temperature of 2 mole of an ideal gas at constant pressure from $30^{\circ} \mathrm{C}$ to $35^{\circ} \mathrm{C}$ The amount of heat required to raise the temperature of the same gas through the same range at constant volume is $\ldots \ldots \ldots \ldots \ldots .$ calorie.(A) 50(B) 30(C) 70(D) 90
Step 1
We can use the formula for heat at constant pressure, which is $Q = nC_p\Delta T$, where $n$ is the number of moles, $C_p$ is the heat capacity at constant pressure, and $\Delta T$ is the change in temperature. Show more…
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70 calories are required to raise the temperature of 2 moles of an ideal gas at constant pressure from $30^{\circ} \mathrm{C}$ to $35^{\circ} \mathrm{C}$. The amount of heat required (in calories) to raise the temperature of the same gas through the same range $\left(30^{\circ} \mathrm{C}\right.$ to $\left.35^{\circ} \mathrm{C}\right)$ at constant volume is (a) 30 (b) 50 (c) 70 (d) 90
If 70 cal of heat is required to raise the temperature of 2 moles of an ideal gas at constant pressure from $30^{\circ} \mathrm{C}$ to $35^{\circ} \mathrm{C}$, then the amount of heat required to raise the temperature of same gas through same range at constant volume is (a) $50 \mathrm{cal}$ (b) $70 \mathrm{cal}$ (c) $60 \mathrm{cal}$ (d) $65 \mathrm{cal}$
Thermodynamics
Round 1
"70 calories of heat are required to raise the temperature of 2 moles of an ideal diatomic gas at constant pressure from 30°C to 35°C. The amount of heat required (in calorie(s)) to raise the temperature of the same through the same range (30 °C to 35 °C) at constant volume is"
Transcript
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