Question
$8-68$ Find the limit. Use l'Hospital's Rule where appropriate. Ifthere is a more elementary method, consider using it. If I'Hospital'sRule doesn't apply, explain why.$$\lim _{x \rightarrow 0^{+}}\left(\frac{1}{x}-\frac{1}{\tan ^{-1} x}\right)$$
Step 1
Step 1: We are given the limit $$\lim _{x \rightarrow 0^{+}}\left(\frac{1}{x}-\frac{1}{\tan ^{-1} x}\right)$$ We can rewrite this as $$\lim _{x \rightarrow 0^{+}}\left(\frac{\tan ^{-1} x - x}{x \tan ^{-1} x}\right)$$ Show more…
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