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$$ 835 \mathrm{km} / \mathrm{h} \text { in a direction } 41.5^{\circ} $$ of north (Fig. $37 ) .$ (a) Findthe components of the velocity vector in the northerly and westerly directions.(b) How far north and how far west has the plane traveled after 2.50 $\mathrm{h}$ ?

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(a) 625 $\mathrm{km} / \mathrm{h}$553 $\mathrm{km} / \mathrm{h}$(b) 1560 $\mathrm{km}$1380 $\mathrm{km}$

Physics 101 Mechanics

Chapter 3

Kinematics in Two or Three Dimensions; Vectors

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

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So for car day, we should first find the components of the velocity vector so we can say velocity in the northern. The northern component components of the velocity vector would be equal to 835 kilometers per hour times co sign of 41.5 degrees and this is going to equal 625 kilometers per hour now. The western component of the velocity would be equal to 835 kilometers per hour and here it would be signed of 41.5 degrees. This is equaling 553 kilometers per hour now to find the total displacement or that the components of the displacement, we can say that the change in the displacement, uh in the northern direction would be equal to the velocity in the northern direction times T. So this would be 625 kilometers per hour multiplied by 2.50 hours. This is giving us 1560 kilometers and then finally, to find the displacement in the Western direction, this would be equal to velocity in the western direction Times T again so 553 kilometers per hour multiplied by 2.50 hours and this is giving us 1380 kilometers. That is the end of the solution. Thank you for watching.

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