00:01
Okay, so we're asked to use the elimination method.
00:05
I'm going to start out with eliminating x.
00:08
What i'm going to do is that.
00:11
Okay, so let's multiply equation 1 by negative 3, and equation 2 by, and if we do that, we get negative 6xx5.
00:29
18 times 3, which is 54.
00:33
And for the second equation, we get 6x plus 4 times 2, which is 8 .y is equal to 19 times 2, which gives us 38.
00:47
Okay, combining these two, we get 8 plus 15, it's 23y is equal to 54 plus 38, and we get 92.
00:59
92 divided by 23 is a 4...