00:01
We're given a function f, which has the formula f of x equals e to the 2x plus e to the negative x.
00:13
In part a, we're asked to find the intervals on which f is increasing or decreasing.
00:22
To do this, first let's find the derivative of f, f prime of x, which is 2e to the 2x minus e to the negative x.
00:31
We see that this is going to be greater than 0.
00:40
If and only if, we have that 2e to 2x is greater than e to the negative x.
00:49
And this is the same as if and only if, either the negative, or sorry, e to the positive 3x, is greater than 1 half, which is true if and only if, 3x is greater than the natural log of 2, the natural log of 1 half, which is true if and only if x is greater than 1 third of natural log of 1 minus the natural log of 2 using log properties, and this is equal to negative 1 3rd natural log of 2.
01:45
And if you must approximate this, this is about equal to negative .23.
01:55
Likewise, we have the f prime of x is less than zero if the opposite is true, so x is less than negative one -third natural log of 2.
02:19
And therefore, it follows that the function f is increasing on the open interval negative 1 3rd natural log of 2 to infinity, and f is decreasing on the open interval negative infinity, negative one -third natural log of 2.
02:44
In part b, we're asked to find the local maximum and minimum values of f.
02:52
To do so, consider when f changes from decreasing to increasing and vice versa, we see that f changes from decreasing to increasing at x equals negative one -third, natural.
03:13
Log of 2, and it never changes from increasing to decreasing...