00:01
The first part of this problem access to draw a circuit diagram of an ammeter connected to a resistor with a value of 10 oms.
00:09
So we'll draw this resistor first that represents the ammeter, label it ra, and then connect the second resistor in series, and add a cell here to complete the circuit.
00:24
And since these two resistors are in series, to solve for the equivalent resistance or the total resistance, all we'd have to do is, is ra plus r, which then gives us the value of 10 .02 oms.
00:44
Now in the third part of this question, we're asked to find what the change in current would be if we assume that the voltage drop across these components will stay the same before and after we add this am meter.
00:59
So what we're going to do here is set up two equations, which describe this problem.
01:05
So we have v, which is going to stay the same, times i1, so we'll call that the current that flows to the circuit before we add the ammeter times r.
01:18
It's going to be equal to the current that flows to the circuit after we add the am meter or i2 times rt.
01:29
And what we want to do is we want to solve for the percentage change of i...