00:01
So we have acetic acid here.
00:04
And if it reaches equilibrium in solution with water, it's going to give off protons and the conjugate base anions.
00:17
So we have an initial grams and milliliters of water.
00:25
But what we have to know is the final, we want to know the final or equilibrium.
00:37
Concentrations of that, that, and that.
00:43
So we got quite a lot of work to do.
00:44
First of all, let's figure out the molarity, the initial molarity or concentration of acetic acid.
00:53
We're going to have to convert grams to moles first, and then we were given milliliters of solution, which we'll have to convert to liters.
01:07
So the grams given to us, we're 0 .0 .0560 grams of acetic acid.
01:21
So now we're going to have to find the molar mass of acetic acid.
01:28
So if you have a periodic table, you would have to look up the mass for carbon.
01:36
There's two carbons.
01:37
There's two oxygens and four hydrogens.
01:44
So you should find 24, 32, 4.
01:51
So your total is going to be 60 grams.
01:57
So then we get rid of our grams.
01:59
That'll leave us with moles.
02:01
And what do we get? a small number of moles, 0 .00093.
02:13
And i'm rounding it to three sig figures, significant figures.
02:17
It goes on beyond that.
02:23
So that's our moles.
02:25
Now we just got to convert milliliters to liters.
02:28
So we had 50 milliliters.
02:36
Just remember every liter has 1 ,000 milliliters.
02:41
So by dividing this by 1 ,000, we get rid of milliliters and are left with liters, which will be 0 .05 liters.
02:52
Now we can get our concentration.
02:55
So let's take our acetic acid.
03:05
The concentration of acetic acid then is 0 .0009333 moles per 0 .05 liters.
03:24
So you divide those together and you'll get 0 .0186 .6...