A $0.1 \mathrm{M}$ acetic acid solution is titrated against $0.1 \mathrm{M}-\mathrm{NaOH}$ solution. What would be the difference in $\mathrm{pH}$ between $1 / 4$ and $3 / 4$ stages of neutralization of the acid?
(a) $2 \log (0.75)$
(b) $2 \log (0.25)$
(c) $\log 3$
(d) $2 \log 3$