00:02
In this question, we will calculate the acid ionization constant.
00:08
Given concentration of the acid, 0 .115m.
00:18
Also given ph is 3 .29.
00:25
Now we know ph is negative logarithm of hydonium ion concentration.
00:35
Therefore, concentration of hydunium ion is 10 to the power negative ph.
00:46
That is 10 to the power negative 3 .29, which will come 5 .13 times 10 to the power negative negative 4.
01:01
Okay, that is the concentration of hydurneum ion.
01:05
Now we have to set up the ice table.
01:09
Let's do that.
01:12
Aj plus h2o, a minus plus h3o plus.
02:08
Now here i, for initial concentration, change concentration and equilibrium concentration.
02:21
Okay, the concentration of the acid here, 0 .115, will ignore this...