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A 0.150 -kg glider is moving to the right on a frictionless. horizontal air track with a speed of 0.80 $\mathrm{m} / \mathrm{s}$ . It has a head-on collision with a $0.300-\mathrm{kg}$ glider that is moving to the left with a speed of 2.20 $\mathrm{m} / \mathrm{s}$ . Find the final velocity (magnitude and direction) of each glider if the collision is elastic.

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$v_{1f}=-3.20 \mathrm{m} / \mathrm{s}$ , $v_{2f}= -0.2 \mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 8

Momentum, Impulse, and Collisions

Moment, Impulse, and Collisions

University of Michigan - Ann Arbor

Hope College

University of Sheffield

Lectures

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

03:30

In physics, impulse is the integral of a force, F, over the time interval, t, for which it acts. Given a force, F, applied for a time, t, the resulting change in momentum, p, is equal to the impulse, I. Impulse applied to a mass, m, is also equal to the change in the object's kinetic energy, T, as a result of the force acting on it.

13:05

A 0.150-kg glider is movin…

04:53

05:32

A $0.150 \mathrm{~kg}$ gli…

03:54

A 0.300 kg glider is movin…

03:10

Two gliders are moving on …

03:37

Two gliders are moving on…

08:09

On a frictionless air trac…

01:00

Two identical gliders, eac…

04:06

$\bullet$ On a frictionles…

01:19

A glider of mass 0.150 $\m…

05:33

$\bullet$ On an air track,…

05:25

Two identical air-track gl…

have mass and one equals to 0.150 kg. And we even initial is equals to 0.80 m per second to go straight. That is positive. And we have m two equals to 0.3 double zero kg and people initially is equal to minus 2.20 m per second. That is towards left. So we move back the for the elastic collision. We will finally will be equals two and one minus m two divided by and one plus m two multiplied by even initial plus two m two They were by M one plus m two multiplied by way to initial. Okay, we two initials substituting values we get even final equals two and 0.15 minus 0.30 There were 0.15 plus 0.30 multiplied by the evil initially 0.80 Okay, plus two multiplied by 30.3, double zero divided by 0.15 plus 0.30 I'm not a player, babe. Minus two point. Oh, Jill. Okay, Hu Jintao, This can be written s minus 2.20 Do you. Okay, so now, after solving it even finally comes out to be minus 3.20 m per second. Okay, so similarly, we two final is given by two and one river by and one plus m two. We even initial Plus I am too minus and one divided by and one plus m two and one plus m two multiplied by way to initial so substituting values we get the two final equals to two multiplied by 0.15 divided by 50.15 plus 0.30 multiplied by 0.80 Okay 0.80 plus 0.30 minus 0.15 divided by 0.15 plus 0.30 and with two i s minus 2.20 So after solving it, the two final comes out to be minus 0.2 meter per second. So we get even final is equals two mhm minus 2.3 point 20 m per second and we two final is equal to minus 0.20 m per second. Okay, so

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