00:01
Okay, so we have a .185 molarity solution of a weak acid.
00:06
Ha, that has a ph of 2 .95.
00:10
We have to calculate the acid ionization constant, k2, or k -a for the acid.
00:17
Okay, so you know that the ph is equal to the negative logs of our h3o plus concentration.
00:27
Well, in this case, we're trying to look for the concentration of h3o plus.
00:30
So that's just equal to 10 to the power of our ph value, or the negative ph value.
00:37
In this case, our ph is 2 .95.
00:40
That gives me 1 .12 .3 molarity.
00:47
Okay.
00:48
Now that we have this concentration, we can actually create our ice table.
00:55
So we have ha reacts with some water to produce a minus and h3o plus.
01:05
We don't include our h2.
01:06
In our ice table because that's just a pure liquid.
01:11
So it's not going to change any of its concentrations.
01:13
So our initial concentration for ha is 0 .185.
01:21
And we know at equilibrium our h3o plus concentration is 1 .1 ,2 times 10 to negative 3...