Question
A 0.218 M solution of the weak acid HX has $\mathrm{pH} 4.57 \mathrm{at} 25^{\circ} \mathrm{C}$. What is $\Delta G^{\circ}$ for the dissociation of the weak acid?$$\mathrm{RNH}_2(a q)+\mathrm{H}_2 \mathrm{O} \rightleftharpoons \mathrm{RNH}_3^{+}(a q)+\mathrm{OH}^{-}(a q)$$
Step 1
The pH is given as 4.57, so we can use the formula: \[ [\mathrm{H}^+] = 10^{-\mathrm{pH}} = 10^{-4.57} \] Calculating this gives: \[ [\mathrm{H}^+] \approx 2.69 \times 10^{-5} \, \text{M} \] Show more…
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