00:04
So in this problem, we are concerned with energy loss and energy transfer due to friction.
00:12
So the first part of the problem asks us to find the amount of kinetic energy transferred into internal energy, given an initial velocity and a final velocity after going around in a circle, for one revolution.
00:31
So in order to find that, we just simply calculate our different.
00:36
In initial and final kinetic energy.
00:40
So we know that our expression for kinetic energy, which we'll call k -e, is equal to 1 half mass times velocity square.
01:01
So to find the amount of energy loss and transferred into internal energy, we'll take delta k -e, which is the change in kinetic energy equal to one half mass parentheses final velocity squared minus the initial velocity squared.
01:41
And in the problem, we're given our values for the mass and these final and initial velocities.
01:48
And we are getting that this value is negative 5 .6 joules, which means that the total amount of energy, lost from mechanical to internal, is simply 5 .6 joules.
02:15
All right.
02:18
So the second part of the problem asks us to consider this change in kinetic energy and then use that to solve for the coefficient of kinetic friction.
02:37
So the most straightforward way to approach this is using our work energy theorem, which states that the change in kinetic energy is equal to the work done on that system.
02:53
And the system in question here is simply a point particle.
03:01
So we know that the only work done on the particle here is work due to friction.
03:07
And we know this change kinetic energy from the last part of the problem.
03:11
So our expression for work can be thought of as the frictional force times the distance the particle travels.
03:29
During this time.
03:33
So we know that this frictional force is going to be coefficient of kinetic friction times mass, times gravity, which is your normal force.
03:46
And we know the distance that it travels in this time is simply one revolution around the circle, which is 2 pi r.
04:02
So if we rearrange this expression and just solve for the coefficient, we're left with the coefficient is equal to the change in kinetic energy, over the mass times gravity times two pi...