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A 0.500 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 40.0 pC charge on its surface. What is the potential near its surface?

$V=144 V$

Physics 102 Electricity and Magnetism

Chapter 19

Electric Potential and Electric Field

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Simon Fraser University

Hope College

University of Winnipeg

Lectures

11:53

In physics, a charge is a …

10:30

The electric force is a ph…

01:11

A Gaussian sphere of radiu…

0:00

Charge $Q = +$4.00 $\mu$C …

01:33

A charge of 6.00 $\mathrm{…

04:45

A spherical conductor with…

04:09

An insulating sphere is 8.…

07:51

A solid plastic sphere of …

03:06

A uniform charge density o…

A total electric charge of…

02:13

(a) A sphere has a surface…

10:54

A solid insulating sphere …

A plastic rod has been ben…

Charge $Q$ is distributed …

02:40

A net charge of $5.0 \mu \…

08:22

A solid conducting sphere …

10:47

A solid sphere of radius 4…

00:42

A van de Graaff generator …

03:15

In Fig. $24-43,$ a plastic…

06:13

Consider a thin, spherical…

02:50

A conducting spherical she…

So here we are asked to find the potential at the surface of the sphere, which is insulating sphere. So this field has the charge on the surface. So it's given that it's 40 pico cooler. Since we don't know that's the sign of the charge. Let's assume that it's positive charge distributed evenly along on the surface, and that's uniformly distributed. So we are given that that's 40 pico column. That means 40 times tend our negative 12 whom So if we were asked to find the potential inside this fear somewhere, it would be difficult task. But we are on the surface off this fear. That means we're outside all the charge collection. So at this surface, or anywhere from the surface to the outside, so it starts from here anywhere to the infinity. We can assume that all the charges constant record at the center of the sphere on dhe, so we need to find the radius first off this because we are now finding the potential on the surface, Toby, The distance now is radius. Since we are given diameter, which is 0.5 centimeters, the radius will be 0.25 centimeter. So from this. This is enough data to find the potential on the surface. Potential is given by caking divided by up. So that will be K is nine times 10 power nine Q Is 40 people pulling? That is 40 times 10 power negative 12 divided by the distance. You just 0.25 times 10 power Negative, too. Uh, that negative too comes from the fact that radius here was in centimeters or we have to do now is to calculate So nine times 40 is, say, 60 divided by 0.25 which is as good as multiplying it by four. So we have. So from this and this we have 10 power positive 11. And this is strange power. Negative 12 which gives us 10 power reality one. So 1440 times 10 power. Negative. What? That is the potential on the surface office theories 1 44 won't. So if you want to find some potential, somewhere here only have to do is find the distance, which is this just from the surface and add to the radius of the sphere on Use it at this, uh, everything else will be constant. I think

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