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A 0.500 -kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change the period to 2.00 s?

1.27 $\mathrm{Kg}$

Physics 101 Mechanics

Physics 103

Chapter 16

Oscillatory Motion and Waves

Periodic Motion

Wave Optics

Rutgers, The State University of New Jersey

Simon Fraser University

University of Winnipeg

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So in this question, we argument the tee off 1.5 for mass, 0.5 kilos and we are asked for the tee off. Two seconds. What a mass must we add to this mess? So for that, using this information, we must find the value of K. So let's use the relation. We know T equals to two pi square root and by K So let's use this. Let's substitute the value of T and em 1.5 and 0.5 here. As you can see, this is M and this is tee. From this we find the body of K as decider suggests, so K is equal to two pi, divided by 1.5 square multiplied by 0.5 gives you the value 8.773 neutrons per meter. Let's use that value to find the mass 40 equals to two. So in this case, T is equal to two mass we don't know que is 8.773 on writing down for the mass. This is value to square here for, as you can see, this shadow suggests, and 8.77 threes K divided by two pi square. If you saw this, you get 0.889 So how much mass must we add? Is delta em by the mass minus initiate mess? So final mass is 0.889 initial most mass. Worse on five. So answer here is 0.389 kilos. So we must add 0.389 kilos. Answer given below question on numerator is wrong

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