00:01
All right guys, we are given the following data for two rooms of air.
00:05
That is tb is equal to 600 degrees centigrade and that is equal to 333 .15 kelvin.
00:18
Now we've got ta is equal to 25 degrees centigrade, 25 degrees centigrade.
00:26
That is 298 .15 kelvin.
00:30
And we've got t2 is equal to 20 degrees centigrade is equal to 293 .15 kelvin.
00:40
Now we've got pa is equal to 500 khal and we've got pb is equal to 200 kilopascal.
00:53
Now guys we've got mb is equal to 4 kg and we've got v a is equal to 1 kg and we've got va is equal to 1 cubic meters so from energy equation for for this problem we've got q is equal to m2 multiplied by u2 is minus m a multiplied by ua multiplied by ua minus m b multiplied by u b plus w so this is the cost of volume pressure so work done is equal to zero and heat transfer is equal to q is equal to m2 into u2 minus ma into u2 minus ma into ua minus mb into ub.
01:58
So from ideal gas equation we can calculate air mass in room a, that is pa into va is equal to ma into r into ta.
02:13
So guys, we've got m .a.
02:16
Is equal to pa into va divided by r into ta...