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A 10 kg mass is attached to the ceiling with two strings (shown below). If the system is in static equilibrium, what is the tension in each of the strings?(A) 50 N(B) 70.7 N(C) 100 N(D) 141.4 N

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Chapter 13

Practice Test 3

Section 1

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Matthew C.

March 2, 2022

Three strings are attached a same middle point. String A goes out and down from the point at an angle of 210 deg from the horizontal to a side wall left of the point. String B goes up from the middle point at an angle of 60 deg where it is attached to

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high in the given problem, A particle of mass 10 kg is attached with the help of two strings. You're like shown in the figure. It is attached with the help of two strings like this, it's sweet MG will be acting vertically downward. two strings each of them are making An angle of 45° with the horizontal. So if you draw a vertical line bisecting the base of the strangle, Then as this angle is 90°.. So this angle will also be 45 Degree each. Suppose the tension created industry is t there will be same tension in each string And this tension may be resolved into two components D. Because theta for both of the strings it will be too costly to and the horizontal component will be peace scientists. Each which will cancel each other. So in equilibrium, the two tensions In the string will be added to give to d cause 45°.. The next tension particularly upwards which will be equal to the weight of the particle. So we can say this is to t into one by route to equals to 10 into 10 means it comes out to be hunted. So attention in one string will be equal to 100 to divided by do. Which comes out to be 50 route to Newton. And if you multiply it by through to it comes out to be 70.7 Newtons. Hence we can see. Yeah, our option B. He is correct. Thank you.

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