00:01
In this question we are given a block on a plate that's attached via a spring to a wall and we are going to displace the plate to set the whole system into subharmonic motion and we're going to find the amplitude and frequency of that motion and then what's the smallest coefficient of friction that will keep block a from slipping on the plate? so let's first note to find this amplitude that this is initially an unstretched spring and then we're going to move plate b 2 .4 inches to the left.
00:44
So our amplitude a which you might also call xm, x max is what that stands for is going to be 2 .4 inches.
00:55
Since that's the furthest that we pulled our system from equilibrium that's the furthest that it can go.
01:02
And now to find the frequency we can find the frequency with the angular frequency divided by 2 pi and that angular frequency is given by the square root of k divided by m.
01:19
So 1 over 2 pi times the square root of k over m.
01:24
In order to do this we're going to need the mass of our system in slugs.
01:31
So we have a total of 40 pounds for the plate plus 10 pounds for the block so that's 50 pounds total divided by 32 .2 feet per second squared and i get a mass of 1 .553 slugs.
01:52
I do tend to keep an extra decimal place or two during calculations and then round at the end to improve the precision of that final answer.
02:03
So we now can take 1 over 2 pi times the square root of 60 pounds per foot divided by 1 .553 slugs and that gets me a frequency of 0 .989 hertz.
02:24
So we are just shy of one complete cycle per second.
02:30
So to find this corresponding smallest allowable value of the coefficient of static friction we need to consider that let's start like let's assume that we're going to start from the maximum displacement right here at the start...