The sample is $55.2 \%$ pure, so the mass of $\mathrm{Fe}_{2} \mathrm{O}_{3}$ in the sample is $1.0 \mathrm{~g} \times 0.552 = 0.552 \mathrm{~g}$. The molar mass of $\mathrm{Fe}_{2} \mathrm{O}_{3}$ is $159.69 \mathrm{~g/mol}$, so the number of moles of
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