Question
A $100 \%$-efficient electric motor is lifting a $20-\mathrm{N}$ weight at $30 \mathrm{~cm} / \mathrm{s}$. How much current does it draw from a $6.0-\mathrm{V}$ battery?
Step 1
We know that 1 meter is equal to 100 centimeters, so we have: \[v = 30 \, \text{cm/s} = 0.30 \, \text{m/s}\] Show more…
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