00:01
Question number 23, the mass is given as m equal to 10 kg and volume is equal to 12 into 10 cm cube.
00:28
The 12 centimeter is the vertical height of the cube and the top surface of the cube is at a depth of h equal to 5 centimeter.
00:44
The force on the top surface of the cube, f top, is equal to the force by the hydrostatic pressure and the force by the atmospheric pressure.
01:02
So we can write row g into the depth of top surface which is 0 .05 meter plus the atmospheric pressure 1 .10 -130 pascal.
01:23
Substituting the values and this pressure is multiplied by the area.
01:31
Substituting the values, thousand into 9 .8 into 0 .05 plus atmospheric pressure 10130.
01:56
This all is multiplied by the area which is 0 .01 meter square.
02:08
Solving this we will get the force on the top surface as 1 .018 into 10 to the power 3 newton.
02:22
Now the force on the bottom surface is fv is equal to the hydrostatic pressure rho gh 1000 into 9 .8 into 9 .8 into 9.
02:44
The depth of the bottom surface which is 12 cm plus 5 cm or 0 .17 plus atmospheric pressure 101300 into the area which is 0 .01...