We know that the molar mass of $\mathrm{PbI}_{2}$ is 461 g/mol. So, we can use the formula:
\[
\text{{Moles of }} \mathrm{PbI}_{2} = \frac{{\text{{mass}}}}{{\text{{molar mass}}}}
\]
Substituting the given values, we get:
\[
\text{{Moles of }} \mathrm{PbI}_{2} =
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