To find the moles of KOH, we use the formula:
\[
\text{Moles of KOH} = \text{Concentration (M)} \times \text{Volume (L)}
\]
Given that the concentration of KOH is 0.60 M and the volume is 50.0 mL (which is 0.0500 L), we have:
\[
\text{Moles of KOH} = 0.60
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