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A $1050-\mathrm{kg}$ sports car is moving westbound at 15.0 $\mathrm{m} / \mathrm{s}$ on a level road when it collides with a 6320 $\mathrm{kg}$ truck driving east on the same road at 10.0 $\mathrm{m} / \mathrm{s}$ . The two vehicles remain locked together after the collision. (a) What is the velocity (magnitude and direction) of the two vehicles just after the collision? (b) At what speed should the truck have been moving so that it and car are both stopped in the collision? (c) Find the change in kinetic energy of the system of two vehicles for the situations of part (a) and part (b). For which situation is the change in kinetic energy greater in magnitude?

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(a) $v_{2}=6.44 \mathrm{m} / \mathrm{s}$ to the east.(b) $v_{B 1}=2.49 \mathrm{m} / \mathrm{s}$ to the east(c) $\Delta K_{(a)}=-281377 \mathrm{J} \quad-\quad \Delta K_{(b)}=-137750.2 \mathrm{J}$

Physics 101 Mechanics

Chapter 8

Momentum, Impulse, and Collisions

Moment, Impulse, and Collisions

Rutgers, The State University of New Jersey

Hope College

University of Sheffield

University of Winnipeg

Lectures

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

03:30

In physics, impulse is the integral of a force, F, over the time interval, t, for which it acts. Given a force, F, applied for a time, t, the resulting change in momentum, p, is equal to the impulse, I. Impulse applied to a mass, m, is also equal to the change in the object's kinetic energy, T, as a result of the force acting on it.

17:15

A 1050-kg sports car is mo…

07:52

03:35

'A 1050-kg sports car…

05:56

A 1050kg sports car is mov…

0:00

A $1200-\mathrm{kg}$ car t…

05:21

A 1200 -kg car traveling i…

04:12

A 1500-kg car moving east …

14:34

When cars are equipped wit…

04:40

A $2150 \mathrm{kg}$ car m…

08:40

A $750 \mathrm{~kg}$ car i…

A $1500 \mathrm{kg}$ car m…

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