Question
A 1.115 g sample of cobalt was heated with sulfur to give $2.025 \mathrm{~g}$ of cobalt sulfide. What is the empirical formula of cobalt sulfide?
Step 1
We do this by dividing the mass by the molar mass of cobalt. The molar mass of cobalt is approximately 58.93 g/mol. So, we have: \[ \frac{1.115 \, \text{g}}{58.93 \, \text{g/mol}} = 0.01892 \, \text{moles of cobalt} \] Show more…
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