00:01
Let us draw a diagram.
00:04
This is the tree and this is ground and total height is 7 .65 meter from the ground of the tree.
00:11
And from here, here is a frisbee which is hanging and from here height 1 .23 meter a dirt has been thrown upward.
00:21
Okay, a dirt has been thrown upward with the speed 17 .7 meter and this is height this.
00:28
Okay.
00:28
So this distance as will be equal to 7 .6.
00:31
5 minus 1 .23 that will be equal to 6 .42 meter.
00:36
So as per the question, we have mass of frisbee m f equals to 114 gram that is 0 .114 kg and mass of dirt md equals to 0 .24 kg that is 240 gram.
00:51
0 .240 clogram okay in the clogram value.
00:57
And speed v or u that is equal to 17.
01:01
7 meter per second of the dirt.
01:04
Okay, this is speed u.
01:05
So now after traveling this distance, this dirt will hit the frisbee with speed v and which can be calculated using third equation as v square equals to u square minus 2gs.
01:20
Minus g is used because motion is upward and gravitational acceleration is acting downward...