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A $115-\Omega$ resistor, a 67.6 -mH inductor, and a $189-\mu$ F capacitor are connected in series to an ac generator. (a) At what frequency will the current in the circuit be a maximum? (b) At what frequency will the impedance of the circuit be a minimum?
a) see workb) 44.5 $\mathrm{Hz}$
Physics 102 Electricity and Magnetism
Chapter 24
Alternating-Current Circuits
Current, Resistance, and Electromotive Force
Direct-Current Circuits
Electromagnetic Induction
Alternating Current
Cornell University
Rutgers, The State University of New Jersey
University of Washington
Hope College
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for the first time thing, you have to remember the following. So there is a relation between the Ari mass voltage and current in the circuit. And this relation is as follows. There are events of alterations. It goes to the R. M s current times. They see this then the hairy mess current is he goes to the harem as voltage divided by an impedance. Now remember the following this is the vocation of alters depends only on the stores and not on anything else. No, The only thing that we can change anything that circuit he's impedance. So to get the maximum current ever we have to couple it. What is the minimum impedance ever. So we have a minimum Impedance, you have the maximum possible are a masquerade. Now remember that the impudence is equal to the square it off r squared, plus the difference between the two react Ince's So it's very easy to see that when this turns is it goes to zero, we have the minimal impedance. Then, because of that, we conclude the following through the biggest ever current that can run for the circuit. Who happened when the reactant is on the same. And when this happens, the circuit is running out residence. And we already know that the resonant frequency of that, sir quite is equals to one divide it by two pi times the square it off the inducted its times the capacitance playing in the values that are given by the problem we get the following resonant frequency one divided by to pi times the square id off 67.6 Time stand to the minor street because off the mili perfect here for us clothes No sorry times 189 times 10 to the minus six Because of the my group prefix here and this is all under a square it then this is approximately 44.5 hertz on the next item we have to calculate what is the frequency that makes the imperials minimum Now, Lord, that in the rest item we had a ready analyzer impedance and concluded that wending attendance is minimal. The current is the maximum and we have further calculated that if the resonant frequency is the one that makes the emptiness minimum, as we had already think when doing the last item and therefore the frequency that minimizes the impudence is the resonant frequency, as we had just seen in the last item. Then the frequency that makes the impudence minimal is approximately 44.5 hertz, which is the resonant frequency That's so great.
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