Question
A 12 -g lead bullet is shot with a speed of $250 \mathrm{~m} / \mathrm{s}$ into a wooden wall. Assuming that $75 \%$ of the kinetic energy is absorbed by the bullet as heat (and $25 \%$ by the wall), what is the final temperature of the bullet?
Step 1
First, we need to find the initial kinetic energy of the bullet. The formula for kinetic energy is KE = (1/2)mv^2, where m is the mass of the bullet and v is its velocity. Show more…
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