Question
A $12 \mathrm{H}$ inductor carries a steady current of $2.0 \mathrm{~A}$. How can a $60 \mathrm{~V}$ self-induced emf be made to appear in the inductor?
Step 1
The self-induced emf (ε) in an inductor is given by the formula: \[ε = L \frac{dI}{dt}\] where L is the inductance of the inductor, dI is the change in current, and dt is the change in time. Show more…
Show all steps
Your feedback will help us improve your experience
Vishal Gupta and 65 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An inductor of 5 H inductance carries a steady current of 2 A. How can a 50 V self induced e.m.f. be made to appear in the inductor ?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD