00:02
So, we want to know the final speed of the 12 -back.
00:04
So we basically start by saying the work upon the 12 -back is equal to the kinetic energy at the end of dragging it.
00:16
So work is the force times the distance, and the kinetic energy is 1 half mb squared.
00:30
You can rearrange that equation, get v on its own.
00:34
And after doing that, the algebra, we get v is equal to the square.
00:39
Of 2 times the force, times the distance, divided by the mass.
00:57
For part a, no friction.
01:00
The force is 36 newton.
01:02
We drag it for 1 .2 meters, and the mass is 4 .3 kilograms.
01:08
And so if we multiply all those out, we get 4 .48 meters for second.
01:19
Okay...