00:01
Hi, the given problem on the horizontal rough surface.
00:05
Suppose this is the wooden block of mass capital m and here this is the clay of mass small m.
00:14
Suppose initial speed of the clay is u then the speed achieved by this wooden block after the impact with clay is v i and its final speed after traveling through 7 .5 meters means vf comes to be zero.
00:34
The weight of the combined block with clay will be acting vertically downward m plus m g so the reaction offered by this surface horizontal surface to this block will be n which is given by n is equal to m plus m into g and force of friction as the block will be moving rightward a force of friction will be acting on it towards left which is given as mu into n or we can say this is mu into m plus m into g then as per newton's second of motion this is also given as the product of mass of this block with the clay and the acceleration produced in this block along with the clay so canceling this m plus m acceleration in the motion of this block or we can say retardation as the block finally comes to rest.
01:34
This comes this will be given as negative of mu into g as this mu is given as 0 .650 then multiplied with 9 .8 meter per second is square.
01:50
Retardation in the motion of this block comes out to be minus v.
01:58
We will keep it as it is, we will calculate it later on.
02:01
Now this is the retardation in the motion of the block.
02:04
Now for the motion of the block, its initial speed is vi.
02:16
This speed is after the impact with the clay.
02:19
And that is missing, we don't know this...