00:01
Solution for the given problem here first we will list the known and unknown values so step one is here partial pressure of nitrogen gas is equal to 725 millimeter of mercury and mass of co2 carbon dioxide is equal to 1 .20 gram and to volume is equal to we have 755 milliliter temperature is equal to we have temperature is 25 so we convert 25 degrees celsius to calvin so 25 plus 273 .15 kelvin is equal to 298 .15 kelvin is equal to 298 .15 kelvin and step two is convert partial pressure of nitrogen gas into standard atmospheric pressure.
01:39
So here, pn, nitrogen is equal to 7 to 5 millimeter of mercury into 1 atm divided by 760 millimeter of mercury.
02:00
So here this unit can sell with this unit and remaining unit is atm standard atmospheric pressure.
02:12
Is equal to we have 0 .953998m.
02:26
And step 3.
02:33
Step 3, conversion of grams into mall.
02:38
Converging of grams into malls.
02:44
So here number of moles of co2 is equal to 1 .20 gram of co2 into 1 .20 gram of co2 into 1 mole of co2 divided by molar mass of co2 095 gram of co2 is equal to we have 0 .027.
03:22
To 6, 7 more of co2.
03:32
And step 4 is by using ideal gas equation to find, by using ideal gas equation to find the partial pressure of co2.
04:02
So here, partial pressure of co2 is equal to number of more of co2 rt...